{"id":12477,"date":"2026-05-13T10:14:53","date_gmt":"2026-05-13T10:14:53","guid":{"rendered":"https:\/\/www.vedprep.com\/exams\/?p=12477"},"modified":"2026-05-13T10:28:18","modified_gmt":"2026-05-13T10:28:18","slug":"physical-properties-of-liquids","status":"publish","type":"post","link":"https:\/\/www.vedprep.com\/exams\/iit-jam\/physical-properties-of-liquids\/","title":{"rendered":"Master Physical properties of liquids (Vapour pressure): IIT JAM 2027"},"content":{"rendered":"<p><strong>Physical properties of liquids<\/strong> (Vapour pressure) For IIT JAM, such as vapour pressure, surface tension, and viscosity play a critical role in understanding the behavior and applications of liquids in various fields, making it a vital topic for IIT JAM aspirants.<\/p>\n<h2><strong>Physical properties of liquids (Vapour pressure) For IIT JAM<\/strong><\/h2>\n<p data-path-to-node=\"1\">If you\u2019ve ever left a bottle of hand sanitizer open and noticed it &#8220;disappeared&#8221; faster than a bottle of water, you\u2019ve already started studying the <b data-path-to-node=\"1\" data-index-in-node=\"148\">physical properties of liquids<\/b>. For anyone eyeing a seat in a top IIT through the JAM 2027 cycle, mastering concepts like <strong>Physical properties of liquids<\/strong>, surface tension, and viscosity isn&#8217;t just about ticking off a syllabus box\u2014it\u2019s about understanding why liquids behave the way they do in a lab and in the real world.<\/p>\n<p data-path-to-node=\"2\">The process of getting comfortable with these ideas starts with looking at pure substances by covering <strong>Physical properties of liquids<\/strong>. Whether you&#8217;re prepping for IIT JAM, CSIR NET, or GATE, you really need to wrap your head around how vapour pressure works. The <a href=\"https:\/\/jam2026.iitb.ac.in\/files\/syllabus_CY.pdf\" rel=\"nofollow noopener\" target=\"_blank\"><strong>IIT JAM syllabus<\/strong><\/a> explicitly lists the &#8220;Physical and Chemical Properties of Pure Substances&#8221; as a core area.<\/p>\n<p data-path-to-node=\"3\">Simply put, the <strong>Physical\u00a0properties of liquids<\/strong> is the pressure exerted by a vapour when it\u2019s in a happy equilibrium with its liquid or solid form at a specific temperature. If you want to dive deeper into the math and theory, P. W. Atkins or I. H. Greenwood\u2019s <i data-path-to-node=\"3\" data-index-in-node=\"241\">Physical Chemistry<\/i> are the gold standards. At <b data-path-to-node=\"3\" data-index-in-node=\"287\">VedPrep<\/b>, we often suggest these as go-to resources because they break down the &#8220;why&#8221; behind the curves and equations you&#8217;ll see on exam day.<\/p>\n<h2><strong>Importance of Physical properties of liquids (Vapour pressure) For IIT JAM: Applications and Concepts<\/strong><\/h2>\n<p data-path-to-node=\"6\"><strong>Physical properties of liquids<\/strong> isn&#8217;t just a number in a table; it\u2019s the secret sauce behind many lab techniques. Take distillation, for example. If you\u2019re trying to separate two liquids, you\u2019re basically playing a game of &#8220;who turns into a gas first?&#8221; The liquid with the higher vapour pressure (the more volatile one) leaves the flask sooner.<\/p>\n<p data-path-to-node=\"7\">In solvent extraction, vapour pressure helps you pick the right liquid for the job. If a solvent is too volatile, it might evaporate before it finishes its work; too stable, and you\u2019ll struggle to get it out of your final product.<\/p>\n<p data-path-to-node=\"8\">This concept also helps us predict boiling points. A liquid boils when its internal <strong>Physical properties of liquids<\/strong><strong>\u00a0match<\/strong>\u00a0the pressure pushing down on it from the atmosphere. This is why water boils faster (and at a lower temperature) in the mountains than it does at sea level. If you&#8217;re looking into industrial heat transfer or fluid flow, these basics are non-negotiable.<\/p>\n<p data-path-to-node=\"9\">Even when things get messy with non-ideal solutions\u2014where molecules don&#8217;t always play nice together\u2014analysing vapour pressure data gives us a window into the thermodynamics of the mixture.<\/p>\n<h2><strong>Physical properties of liquids (Vapour pressure) For IIT JAM<\/strong><\/h2>\n<p data-path-to-node=\"12\">To really nail those JAM questions, you\u2019ve got to move past the definition. You need to see how the <strong>Physical properties of liquids<\/strong> transform as per environment<strong>.<\/strong>\u00a0At <a href=\"https:\/\/www.vedprep.com\/online-courses\"><strong>VedPrep<\/strong><\/a>, we recommend a two-step approach:<\/p>\n<ol start=\"1\" data-path-to-node=\"13\">\n<li>\n<p data-path-to-node=\"13,0,0\">Get the basics down cold (what is equilibrium, really?).<\/p>\n<\/li>\n<li>\n<p data-path-to-node=\"13,1,0\">Hammer out practice problems, especially those involving the Clausius-Clapeyron equation.<\/p>\n<\/li>\n<\/ol>\n<p data-path-to-node=\"14\">Understanding how intermolecular forces\u2014like those pesky hydrogen bonds\u2014hold molecules back from escaping into the air is key. The stronger the &#8220;hug&#8221; between molecules, the lower the vapour pressure.\u00a0By following a structured study plan and utilizing resources like <a href=\"https:\/\/www.vedprep.com\/online-courses\/iit-jam\"><strong>VedPrep<\/strong><\/a>, students can develop a deep understanding of vapour pressure and its applications in\u00a0 Vapour pressure For IIT JAM, ultimately achieving success in IIT JAM and other competitive exams.<\/p>\n<h2><strong>Physical properties of liquids (Vapour pressure) For IIT JAM: Common Misconceptions\u00a0<\/strong><\/h2>\n<p data-path-to-node=\"17\">One big trap students fall into is treating vapour pressure and atmospheric pressure like they\u2019re the same thing. They aren&#8217;t. Atmospheric pressure is the weight of the air above you; vapour pressure is the &#8220;escape push&#8221; of the liquid itself.<\/p>\n<p data-path-to-node=\"18\">Another myth is that vapour pressure is a fixed constant. It\u2019s actually very moody\u2014it changes as soon as you change the temperature. Think about a cup of hot chai versus a glass of ice water. The hot chai has much more &#8220;steam&#8221; (vapour) coming off it because the higher temperature gives molecules the energy to break free.<\/p>\n<p data-path-to-node=\"18\"><strong>Example<\/strong>: Compare water and ethanol. Water is like a group of friends holding hands tightly (hydrogen bonding), so it has a lower vapour pressure. Ethanol is a bit more relaxed, with weaker forces, so its molecules jump into the gas phase much more easily.<\/p>\n<h2><strong>Worked Example: Calculating Vapour Pressure using Raoult&#8217;s Law<\/strong><\/h2>\n<p>Raoult\u2019s Law is your best friend for ideal solutions. It tells us that the partial pressure of a component is just its &#8220;pure&#8221; pressure multiplied by how much of it is in the mix (mole fraction).<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-14127 aligncenter\" src=\"https:\/\/www.vedprep.com\/exams\/wp-content\/uploads\/Raoults-Law.png\" alt=\"Raoult's Law\" width=\"213\" height=\"95\" \/><\/p>\n<ul>\n<li>\n<p data-path-to-node=\"24\">Let\u2019s imagine a fictional scenario: You\u2019ve got a solution that is 20% ethanol and 80% water (by mole) at 25\u00b0C.<\/p>\n<ul data-path-to-node=\"25\">\n<li>\n<p data-path-to-node=\"25,0,0\">Pure water pressure (<span class=\"math-inline\" data-math=\"P^\\circ_{water}\" data-index-in-node=\"21\">P\u00b0<sub>water<\/sub><\/span>): <b data-path-to-node=\"25,0,0\" data-index-in-node=\"39\">23.76 mmHg<\/b><\/p>\n<\/li>\n<li>\n<p data-path-to-node=\"25,1,0\">Pure ethanol pressure (<span class=\"math-inline\" data-math=\"P^\\circ_{ethanol}\" data-index-in-node=\"23\">P\u00b0<sub>ethanol<\/sub><\/span>): <b data-path-to-node=\"25,1,0\" data-index-in-node=\"43\">58.9 mmHg<\/b><\/p>\n<\/li>\n<\/ul>\n<p data-path-to-node=\"26\">To find the total vapour pressure, you\u2019d calculate:<\/p>\n<div data-path-to-node=\"27\">\n<div class=\"math-block\" data-math=\"P_{total} = (0.80 \\times 23.76) + (0.20 \\times 58.9)\">P<sub>total<\/sub> = (0.80 \u00d7 23.76) + (0.20 \u00d7 58.9)<\/div>\n<\/div>\n<div data-path-to-node=\"28\">\n<div class=\"math-block\" data-math=\"P_{total} = 19.01 + 11.78 = 30.79 \\text{ mmHg}\">P<sub>total<\/sub> = 19.01 + 11.78 = 30.79\u00a0 mmHg<\/div>\n<\/div>\n<\/li>\n<\/ul>\n<h2><strong>Surface Tension and Viscosity: Related Properties of Liquids<\/strong><\/h2>\n<p data-path-to-node=\"32\">While vapour pressure is about &#8220;escaping,&#8221; surface tension is about &#8220;holding on.&#8221; It\u2019s the energy needed to stretch the surface of a liquid. Imagine a water strider walking on a pond\u2014that\u2019s surface tension in action. It happens because the molecules on top don&#8217;t have neighbours above them to pull on, so they pull tighter on the ones beside and below them.<\/p>\n<p data-path-to-node=\"33\">Viscosity is just a fancy word for &#8220;thickness&#8221; or resistance to flow. Think of the difference between pouring water and pouring honey. Honey has high viscosity; it\u2019s sticky and slow. Both of these properties depend heavily on intermolecular forces and temperature. If you heat up honey, it gets &#8220;thinner&#8221; and flows faster because the heat helps the molecules slide past each other more easily.<\/p>\n<h2><strong>Real-World Applications : Examples and Case Studies<\/strong><\/h2>\n<p data-path-to-node=\"36\">Engineers use vapour pressure to design the massive distillation columns that give us gasoline and medicine. Without accurate vapour pressure data, these towers wouldn&#8217;t work, and we\u2019d be stuck with impure products.<\/p>\n<p data-path-to-node=\"37\">Even your laundry detergent depends on this. Companies have to balance the &#8220;volatility&#8221; of the scents and cleaning agents. If the vapour pressure of the fragrance is too high, your clothes stop smelling fresh five minutes after they dry. If it\u2019s too low, you won&#8217;t smell anything at all.<\/p>\n<p data-path-to-node=\"38\">Lastly, meteorologists use these same principles to predict the weather. Humidity is essentially just the vapour pressure of water in our atmosphere. When that pressure changes, it&#8217;s the difference between a sunny day and a thunderstorm.<\/p>\n<h2 data-path-to-node=\"0\"><b data-path-to-node=\"0\" data-index-in-node=\"0\">Final Thoughts<\/b><\/h2>\n<p data-path-to-node=\"1\">Mastering the <b data-path-to-node=\"1\" data-index-in-node=\"14\">Physical properties of liquids (Vapour pressure)<\/b> is more than just a syllabus requirement; it is a foundational step toward excelling in the physical chemistry sections of <b data-path-to-node=\"1\" data-index-in-node=\"186\">IIT JAM 2027. <\/b>\u00a0By understanding how molecular interactions and temperature dictate macro-level behaviors like evaporation and boiling, aspirants can transition from rote memorization to analytical problem-solving. Whether you are calculating deviations using Raoult\u2019s Law or predicting distillation efficiency, a clear conceptual grasp of these properties will be your greatest asset. As you continue your preparation, focus on the interconnectedness of these liquid states to build the academic rigor necessary for a top-tier rank.<\/p>\n<p data-path-to-node=\"1\">To know more in detail from our faculty, watch our YouTube video:<\/p>\n<p class=\"responsive-video-wrap clr\"><iframe title=\"Surface Chemistry | Physical Chemistry | Capsule Course |Part-2|IIT JAM|CSIR NET|GATE| Chem Academy\" width=\"1200\" height=\"675\" src=\"https:\/\/www.youtube.com\/embed\/VY_275NuRC4?list=PLdZcCa6mtW21nnnBxv13THPr99MxKMmrO\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" referrerpolicy=\"strict-origin-when-cross-origin\" allowfullscreen><\/iframe><\/p>\n<section>\n<h2><strong>Frequently Asked Questions<\/strong><\/h2>\n<div><style>#sp-ea-14133 .spcollapsing { height: 0; overflow: hidden; transition-property: height;transition-duration: 300ms;}#sp-ea-14133.sp-easy-accordion>.sp-ea-single {margin-bottom: 10px; border: 1px solid #e2e2e2; }#sp-ea-14133.sp-easy-accordion>.sp-ea-single>.ea-header a {color: #444;}#sp-ea-14133.sp-easy-accordion>.sp-ea-single>.sp-collapse>.ea-body {background: #fff; color: #444;}#sp-ea-14133.sp-easy-accordion>.sp-ea-single {background: #eee;}#sp-ea-14133.sp-easy-accordion>.sp-ea-single>.ea-header a .ea-expand-icon { float: left; color: #444;font-size: 16px;}<\/style><div id=\"sp_easy_accordion-1777290385\">\n<div id=\"sp-ea-14133\" class=\"sp-ea-one sp-easy-accordion\" data-ea-active=\"ea-click\" data-ea-mode=\"vertical\" data-preloader=\"\" data-scroll-active-item=\"\" data-offset-to-scroll=\"0\">\n\n<!-- Start accordion card div. -->\n<div class=\"ea-card ea-expand sp-ea-single\">\n\t<!-- Start accordion header. -->\n\t<h3 class=\"ea-header\">\n\t\t<!-- Add anchor tag for header. -->\n\t\t<a class=\"collapsed\" id=\"ea-header-141330\" role=\"button\" data-sptoggle=\"spcollapse\" data-sptarget=\"#collapse141330\" aria-controls=\"collapse141330\" href=\"#\"  aria-expanded=\"true\" tabindex=\"0\">\n\t\t<i aria-hidden=\"true\" role=\"presentation\" class=\"ea-expand-icon eap-icon-ea-expand-minus\"><\/i> What exactly is vapour pressure?\t\t<\/a> <!-- Close anchor tag for header. -->\n\t<\/h3>\t<!-- Close header tag. -->\n\t<!-- Start collapsible content div. -->\n\t<div class=\"sp-collapse spcollapse collapsed show\" id=\"collapse141330\" data-parent=\"#sp-ea-14133\" role=\"region\" aria-labelledby=\"ea-header-141330\">  <!-- Content div. -->\n\t\t<div class=\"ea-body\">\n\t\t<p>Vapour pressure is the pressure exerted by a vapour that is in thermodynamic equilibrium with its liquid or solid phase at a specific temperature in a closed system.<\/p>\n\t\t<\/div> <!-- Close content div. -->\n\t<\/div> <!-- Close collapse div. -->\n<\/div> <!-- Close card div. -->\n<!-- Start accordion card div. -->\n<div class=\"ea-card  sp-ea-single\">\n\t<!-- Start accordion header. -->\n\t<h3 class=\"ea-header\">\n\t\t<!-- Add anchor tag for header. -->\n\t\t<a class=\"collapsed\" id=\"ea-header-141331\" role=\"button\" data-sptoggle=\"spcollapse\" data-sptarget=\"#collapse141331\" aria-controls=\"collapse141331\" href=\"#\"  aria-expanded=\"false\" tabindex=\"0\">\n\t\t<i aria-hidden=\"true\" role=\"presentation\" class=\"ea-expand-icon eap-icon-ea-expand-plus\"><\/i> Is vapour pressure the same as atmospheric pressure?\t\t<\/a> <!-- Close anchor tag for header. -->\n\t<\/h3>\t<!-- Close header tag. -->\n\t<!-- Start collapsible content div. -->\n\t<div class=\"sp-collapse spcollapse \" id=\"collapse141331\" data-parent=\"#sp-ea-14133\" role=\"region\" aria-labelledby=\"ea-header-141331\">  <!-- Content div. -->\n\t\t<div class=\"ea-body\">\n\t\t<p>No. Vapour pressure is an intrinsic property of a substance based on its temperature and molecular makeup, while atmospheric pressure is the external pressure exerted by the weight of the air above us.<\/p>\n\t\t<\/div> <!-- Close content div. -->\n\t<\/div> <!-- Close collapse div. -->\n<\/div> <!-- Close card div. -->\n<!-- Start accordion card div. -->\n<div class=\"ea-card  sp-ea-single\">\n\t<!-- Start accordion header. -->\n\t<h3 class=\"ea-header\">\n\t\t<!-- Add anchor tag for header. -->\n\t\t<a class=\"collapsed\" id=\"ea-header-141332\" role=\"button\" data-sptoggle=\"spcollapse\" data-sptarget=\"#collapse141332\" aria-controls=\"collapse141332\" href=\"#\"  aria-expanded=\"false\" tabindex=\"0\">\n\t\t<i aria-hidden=\"true\" role=\"presentation\" class=\"ea-expand-icon eap-icon-ea-expand-plus\"><\/i> What is the relationship between temperature and vapour pressure?\t\t<\/a> <!-- Close anchor tag for header. -->\n\t<\/h3>\t<!-- Close header tag. -->\n\t<!-- Start collapsible content div. -->\n\t<div class=\"sp-collapse spcollapse \" id=\"collapse141332\" data-parent=\"#sp-ea-14133\" role=\"region\" aria-labelledby=\"ea-header-141332\">  <!-- Content div. -->\n\t\t<div class=\"ea-body\">\n\t\t<p>They are directly proportional. As temperature increases, the kinetic energy of molecules increases, allowing more of them to escape into the gas phase, which raises the vapour pressure.<\/p>\n\t\t<\/div> <!-- Close content div. -->\n\t<\/div> <!-- Close collapse div. -->\n<\/div> <!-- Close card div. -->\n<!-- Start accordion card div. -->\n<div class=\"ea-card  sp-ea-single\">\n\t<!-- Start accordion header. -->\n\t<h3 class=\"ea-header\">\n\t\t<!-- Add anchor tag for header. -->\n\t\t<a class=\"collapsed\" id=\"ea-header-141333\" role=\"button\" data-sptoggle=\"spcollapse\" data-sptarget=\"#collapse141333\" aria-controls=\"collapse141333\" href=\"#\"  aria-expanded=\"false\" tabindex=\"0\">\n\t\t<i aria-hidden=\"true\" role=\"presentation\" class=\"ea-expand-icon eap-icon-ea-expand-plus\"><\/i> How do intermolecular forces affect vapour pressure?\t\t<\/a> <!-- Close anchor tag for header. -->\n\t<\/h3>\t<!-- Close header tag. -->\n\t<!-- Start collapsible content div. -->\n\t<div class=\"sp-collapse spcollapse \" id=\"collapse141333\" data-parent=\"#sp-ea-14133\" role=\"region\" aria-labelledby=\"ea-header-141333\">  <!-- Content div. -->\n\t\t<div class=\"ea-body\">\n\t\t<p>There is an inverse relationship. Stronger intermolecular forces (like hydrogen bonding in water) hold molecules together more tightly, resulting in a lower vapour pressure compared to liquids with weak forces.<\/p>\n\t\t<\/div> <!-- Close content div. -->\n\t<\/div> <!-- Close collapse div. -->\n<\/div> <!-- Close card div. -->\n<!-- Start accordion card div. -->\n<div class=\"ea-card  sp-ea-single\">\n\t<!-- Start accordion header. -->\n\t<h3 class=\"ea-header\">\n\t\t<!-- Add anchor tag for header. -->\n\t\t<a class=\"collapsed\" id=\"ea-header-141334\" role=\"button\" data-sptoggle=\"spcollapse\" data-sptarget=\"#collapse141334\" aria-controls=\"collapse141334\" href=\"#\"  aria-expanded=\"false\" tabindex=\"0\">\n\t\t<i aria-hidden=\"true\" role=\"presentation\" class=\"ea-expand-icon eap-icon-ea-expand-plus\"><\/i> What does \"volatile\" mean in the context of vapour pressure?\t\t<\/a> <!-- Close anchor tag for header. -->\n\t<\/h3>\t<!-- Close header tag. -->\n\t<!-- Start collapsible content div. -->\n\t<div class=\"sp-collapse spcollapse \" id=\"collapse141334\" data-parent=\"#sp-ea-14133\" role=\"region\" aria-labelledby=\"ea-header-141334\">  <!-- Content div. -->\n\t\t<div class=\"ea-body\">\n\t\t<p>A volatile liquid is one that has a high vapour pressure at room temperature, meaning it evaporates easily (e.g., acetone or ethanol).<\/p>\n\t\t<\/div> <!-- Close content div. -->\n\t<\/div> <!-- Close collapse div. -->\n<\/div> <!-- Close card div. -->\n<!-- Start accordion card div. -->\n<div class=\"ea-card  sp-ea-single\">\n\t<!-- Start accordion header. -->\n\t<h3 class=\"ea-header\">\n\t\t<!-- Add anchor tag for header. -->\n\t\t<a class=\"collapsed\" id=\"ea-header-141335\" role=\"button\" data-sptoggle=\"spcollapse\" data-sptarget=\"#collapse141335\" aria-controls=\"collapse141335\" href=\"#\"  aria-expanded=\"false\" tabindex=\"0\">\n\t\t<i aria-hidden=\"true\" role=\"presentation\" class=\"ea-expand-icon eap-icon-ea-expand-plus\"><\/i> When does a solution follow Raoult\u2019s Law?\t\t<\/a> <!-- Close anchor tag for header. -->\n\t<\/h3>\t<!-- Close header tag. -->\n\t<!-- Start collapsible content div. -->\n\t<div class=\"sp-collapse spcollapse \" id=\"collapse141335\" data-parent=\"#sp-ea-14133\" role=\"region\" aria-labelledby=\"ea-header-141335\">  <!-- Content div. -->\n\t\t<div class=\"ea-body\">\n\t\t<p>A solution follows Raoult\u2019s Law when it is an <b data-path-to-node=\"10\" data-index-in-node=\"91\">ideal solution<\/b>, meaning the interactions between different molecules (A-B) are similar to the interactions between like molecules (A-A and B-B).<\/p>\n\t\t<\/div> <!-- Close content div. -->\n\t<\/div> <!-- Close collapse div. -->\n<\/div> <!-- Close card div. -->\n<!-- Start accordion card div. -->\n<div class=\"ea-card  sp-ea-single\">\n\t<!-- Start accordion header. -->\n\t<h3 class=\"ea-header\">\n\t\t<!-- Add anchor tag for header. -->\n\t\t<a class=\"collapsed\" id=\"ea-header-141336\" role=\"button\" data-sptoggle=\"spcollapse\" data-sptarget=\"#collapse141336\" aria-controls=\"collapse141336\" href=\"#\"  aria-expanded=\"false\" tabindex=\"0\">\n\t\t<i aria-hidden=\"true\" role=\"presentation\" class=\"ea-expand-icon eap-icon-ea-expand-plus\"><\/i> What is the Clausius-Clapeyron equation used for?\t\t<\/a> <!-- Close anchor tag for header. -->\n\t<\/h3>\t<!-- Close header tag. -->\n\t<!-- Start collapsible content div. -->\n\t<div class=\"sp-collapse spcollapse \" id=\"collapse141336\" data-parent=\"#sp-ea-14133\" role=\"region\" aria-labelledby=\"ea-header-141336\">  <!-- Content div. -->\n\t\t<div class=\"ea-body\">\n\t\t<p>It is used to calculate the vapour pressure of a substance at different temperatures or to determine the enthalpy of vaporization (\u0394<span class=\"math-inline\" data-math=\"\\Delta H_{vap}\" data-index-in-node=\"184\">H<sub>vap<\/sub><\/span>) by measuring how vapour pressure changes with temperature.<\/p>\n\t\t<\/div> <!-- Close content div. -->\n\t<\/div> <!-- Close collapse div. -->\n<\/div> <!-- Close card div. -->\n<!-- Start accordion card div. -->\n<div class=\"ea-card  sp-ea-single\">\n\t<!-- Start accordion header. -->\n\t<h3 class=\"ea-header\">\n\t\t<!-- Add anchor tag for header. -->\n\t\t<a class=\"collapsed\" id=\"ea-header-141337\" role=\"button\" data-sptoggle=\"spcollapse\" data-sptarget=\"#collapse141337\" aria-controls=\"collapse141337\" href=\"#\"  aria-expanded=\"false\" tabindex=\"0\">\n\t\t<i aria-hidden=\"true\" role=\"presentation\" class=\"ea-expand-icon eap-icon-ea-expand-plus\"><\/i> What is \"Relative Lowering of Vapour Pressure\"?\t\t<\/a> <!-- Close anchor tag for header. -->\n\t<\/h3>\t<!-- Close header tag. -->\n\t<!-- Start collapsible content div. -->\n\t<div class=\"sp-collapse spcollapse \" id=\"collapse141337\" data-parent=\"#sp-ea-14133\" role=\"region\" aria-labelledby=\"ea-header-141337\">  <!-- Content div. -->\n\t\t<div class=\"ea-body\">\n\t\t<p>It is a colligative property where the addition of a non-volatile solute reduces the vapour pressure of the solvent. The ratio of this decrease to the pure solvent's pressure equals the mole fraction of the solute.<\/p>\n\t\t<\/div> <!-- Close content div. -->\n\t<\/div> <!-- Close collapse div. -->\n<\/div> <!-- Close card div. -->\n<!-- Start accordion card div. -->\n<div class=\"ea-card  sp-ea-single\">\n\t<!-- Start accordion header. -->\n\t<h3 class=\"ea-header\">\n\t\t<!-- Add anchor tag for header. -->\n\t\t<a class=\"collapsed\" id=\"ea-header-141338\" role=\"button\" data-sptoggle=\"spcollapse\" data-sptarget=\"#collapse141338\" aria-controls=\"collapse141338\" href=\"#\"  aria-expanded=\"false\" tabindex=\"0\">\n\t\t<i aria-hidden=\"true\" role=\"presentation\" class=\"ea-expand-icon eap-icon-ea-expand-plus\"><\/i> Do all liquids follow Raoult's Law?\t\t<\/a> <!-- Close anchor tag for header. -->\n\t<\/h3>\t<!-- Close header tag. -->\n\t<!-- Start collapsible content div. -->\n\t<div class=\"sp-collapse spcollapse \" id=\"collapse141338\" data-parent=\"#sp-ea-14133\" role=\"region\" aria-labelledby=\"ea-header-141338\">  <!-- Content div. -->\n\t\t<div class=\"ea-body\">\n\t\t<p>No. Non-ideal solutions show \"positive\" or \"negative\" deviations depending on whether the intermolecular attractions between the solute and solvent are weaker or stronger than in the pure components.<\/p>\n\t\t<\/div> <!-- Close content div. -->\n\t<\/div> <!-- Close collapse div. -->\n<\/div> <!-- Close card div. -->\n<!-- Start accordion card div. -->\n<div class=\"ea-card  sp-ea-single\">\n\t<!-- Start accordion header. -->\n\t<h3 class=\"ea-header\">\n\t\t<!-- Add anchor tag for header. -->\n\t\t<a class=\"collapsed\" id=\"ea-header-141339\" role=\"button\" data-sptoggle=\"spcollapse\" data-sptarget=\"#collapse141339\" aria-controls=\"collapse141339\" href=\"#\"  aria-expanded=\"false\" tabindex=\"0\">\n\t\t<i aria-hidden=\"true\" role=\"presentation\" class=\"ea-expand-icon eap-icon-ea-expand-plus\"><\/i> How is boiling point defined in terms of vapour pressure?\t\t<\/a> <!-- Close anchor tag for header. -->\n\t<\/h3>\t<!-- Close header tag. -->\n\t<!-- Start collapsible content div. -->\n\t<div class=\"sp-collapse spcollapse \" id=\"collapse141339\" data-parent=\"#sp-ea-14133\" role=\"region\" aria-labelledby=\"ea-header-141339\">  <!-- Content div. -->\n\t\t<div class=\"ea-body\">\n\t\t<p>The boiling point is the temperature at which the vapour pressure of the liquid becomes equal to the external atmospheric pressure.<\/p>\n\t\t<\/div> <!-- Close content div. -->\n\t<\/div> <!-- Close collapse div. -->\n<\/div> <!-- Close card div. -->\n<!-- Start accordion card div. -->\n<div class=\"ea-card  sp-ea-single\">\n\t<!-- Start accordion header. -->\n\t<h3 class=\"ea-header\">\n\t\t<!-- Add anchor tag for header. -->\n\t\t<a class=\"collapsed\" id=\"ea-header-1413310\" role=\"button\" data-sptoggle=\"spcollapse\" data-sptarget=\"#collapse1413310\" aria-controls=\"collapse1413310\" href=\"#\"  aria-expanded=\"false\" tabindex=\"0\">\n\t\t<i aria-hidden=\"true\" role=\"presentation\" class=\"ea-expand-icon eap-icon-ea-expand-plus\"><\/i> Why do liquids boil at lower temperatures at high altitudes?\t\t<\/a> <!-- Close anchor tag for header. -->\n\t<\/h3>\t<!-- Close header tag. -->\n\t<!-- Start collapsible content div. -->\n\t<div class=\"sp-collapse spcollapse \" id=\"collapse1413310\" data-parent=\"#sp-ea-14133\" role=\"region\" aria-labelledby=\"ea-header-1413310\">  <!-- Content div. -->\n\t\t<div class=\"ea-body\">\n\t\t<p>At high altitudes, atmospheric pressure is lower. Since a liquid only needs to reach a lower vapour pressure to match the surrounding pressure, it boils sooner.<\/p>\n\t\t<\/div> <!-- Close content div. -->\n\t<\/div> <!-- Close collapse div. -->\n<\/div> <!-- Close card div. -->\n<!-- Start accordion card div. -->\n<div class=\"ea-card  sp-ea-single\">\n\t<!-- Start accordion header. -->\n\t<h3 class=\"ea-header\">\n\t\t<!-- Add anchor tag for header. -->\n\t\t<a class=\"collapsed\" id=\"ea-header-1413311\" role=\"button\" data-sptoggle=\"spcollapse\" data-sptarget=\"#collapse1413311\" aria-controls=\"collapse1413311\" href=\"#\"  aria-expanded=\"false\" tabindex=\"0\">\n\t\t<i aria-hidden=\"true\" role=\"presentation\" class=\"ea-expand-icon eap-icon-ea-expand-plus\"><\/i> What is the \"Normal Boiling Point\"?\t\t<\/a> <!-- Close anchor tag for header. -->\n\t<\/h3>\t<!-- Close header tag. -->\n\t<!-- Start collapsible content div. -->\n\t<div class=\"sp-collapse spcollapse \" id=\"collapse1413311\" data-parent=\"#sp-ea-14133\" role=\"region\" aria-labelledby=\"ea-header-1413311\">  <!-- Content div. -->\n\t\t<div class=\"ea-body\">\n\t\t<p>The normal boiling point is the temperature at which a liquid's vapour pressure equals exactly <b data-path-to-node=\"18\" data-index-in-node=\"135\">1 atm<\/b> (760 mmHg).<\/p>\n\t\t<\/div> <!-- Close content div. -->\n\t<\/div> <!-- Close collapse div. -->\n<\/div> <!-- Close card div. -->\n<!-- Start accordion card div. -->\n<div class=\"ea-card  sp-ea-single\">\n\t<!-- Start accordion header. -->\n\t<h3 class=\"ea-header\">\n\t\t<!-- Add anchor tag for header. -->\n\t\t<a class=\"collapsed\" id=\"ea-header-1413312\" role=\"button\" data-sptoggle=\"spcollapse\" data-sptarget=\"#collapse1413312\" aria-controls=\"collapse1413312\" href=\"#\"  aria-expanded=\"false\" tabindex=\"0\">\n\t\t<i aria-hidden=\"true\" role=\"presentation\" class=\"ea-expand-icon eap-icon-ea-expand-plus\"><\/i> What happens to vapour pressure at the critical point?\t\t<\/a> <!-- Close anchor tag for header. -->\n\t<\/h3>\t<!-- Close header tag. -->\n\t<!-- Start collapsible content div. -->\n\t<div class=\"sp-collapse spcollapse \" id=\"collapse1413312\" data-parent=\"#sp-ea-14133\" role=\"region\" aria-labelledby=\"ea-header-1413312\">  <!-- Content div. -->\n\t\t<div class=\"ea-body\">\n\t\t<p>At the critical point, the distinction between the liquid and gas phases disappears, and the vapour pressure reaches its maximum value where the two phases coexist.<\/p>\n\t\t<\/div> <!-- Close content div. -->\n\t<\/div> <!-- Close collapse div. -->\n<\/div> <!-- Close card div. -->\n<!-- Start accordion card div. -->\n<div class=\"ea-card  sp-ea-single\">\n\t<!-- Start accordion header. -->\n\t<h3 class=\"ea-header\">\n\t\t<!-- Add anchor tag for header. -->\n\t\t<a class=\"collapsed\" id=\"ea-header-1413313\" role=\"button\" data-sptoggle=\"spcollapse\" data-sptarget=\"#collapse1413313\" aria-controls=\"collapse1413313\" href=\"#\"  aria-expanded=\"false\" tabindex=\"0\">\n\t\t<i aria-hidden=\"true\" role=\"presentation\" class=\"ea-expand-icon eap-icon-ea-expand-plus\"><\/i> How are surface tension and vapour pressure related?\t\t<\/a> <!-- Close anchor tag for header. -->\n\t<\/h3>\t<!-- Close header tag. -->\n\t<!-- Start collapsible content div. -->\n\t<div class=\"sp-collapse spcollapse \" id=\"collapse1413313\" data-parent=\"#sp-ea-14133\" role=\"region\" aria-labelledby=\"ea-header-1413313\">  <!-- Content div. -->\n\t\t<div class=\"ea-body\">\n\t\t<p>Both are governed by intermolecular forces. Generally, a liquid with high surface tension (stronger forces) will have a lower vapour pressure.<\/p>\n\t\t<\/div> <!-- Close content div. -->\n\t<\/div> <!-- Close collapse div. -->\n<\/div> <!-- Close card div. -->\n<!-- Start accordion card div. -->\n<div class=\"ea-card  sp-ea-single\">\n\t<!-- Start accordion header. -->\n\t<h3 class=\"ea-header\">\n\t\t<!-- Add anchor tag for header. -->\n\t\t<a class=\"collapsed\" id=\"ea-header-1413314\" role=\"button\" data-sptoggle=\"spcollapse\" data-sptarget=\"#collapse1413314\" aria-controls=\"collapse1413314\" href=\"#\"  aria-expanded=\"false\" tabindex=\"0\">\n\t\t<i aria-hidden=\"true\" role=\"presentation\" class=\"ea-expand-icon eap-icon-ea-expand-plus\"><\/i> Does viscosity change with vapour pressure?\t\t<\/a> <!-- Close anchor tag for header. -->\n\t<\/h3>\t<!-- Close header tag. -->\n\t<!-- Start collapsible content div. -->\n\t<div class=\"sp-collapse spcollapse \" id=\"collapse1413314\" data-parent=\"#sp-ea-14133\" role=\"region\" aria-labelledby=\"ea-header-1413314\">  <!-- Content div. -->\n\t\t<div class=\"ea-body\">\n\t\t<p>Not directly, but they share a common cause: temperature. Increasing temperature decreases viscosity (easier flow) and increases vapour pressure (easier evaporation).<\/p>\n\t\t<\/div> <!-- Close content div. -->\n\t<\/div> <!-- Close collapse div. -->\n<\/div> <!-- Close card div. -->\n<\/div>\n<\/div>\n<\/div>\n<\/section>\n","protected":false},"excerpt":{"rendered":"<p>Physical properties of liquids (Vapour pressure) For IIT JAM, such as vapour pressure, surface tension, and viscosity, play a critical role in understanding the behavior and applications of liquids in various fields, making it a vital topic for IIT JAM aspirants. Physical properties of liquids (Vapour pressure) For IIT JAM The process involves understanding the properties of pure substances.<\/p>\n","protected":false},"author":11,"featured_media":12476,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"footnotes":"","rank_math_seo_score":86},"categories":[23],"tags":[2923,861,7289,7290,7291,2922],"class_list":["post-12477","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-iit-jam","tag-competitive-exams","tag-physical-chemistry","tag-physical-properties-of-liquids-vapour-pressure-for-iit-jam","tag-physical-properties-of-liquids-vapour-pressure-for-iit-jam-notes","tag-physical-properties-of-liquids-vapour-pressure-for-iit-jam-questions","tag-vedprep","entry","has-media"],"acf":[],"_links":{"self":[{"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/posts\/12477","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/users\/11"}],"replies":[{"embeddable":true,"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/comments?post=12477"}],"version-history":[{"count":9,"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/posts\/12477\/revisions"}],"predecessor-version":[{"id":16030,"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/posts\/12477\/revisions\/16030"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/media\/12476"}],"wp:attachment":[{"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/media?parent=12477"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/categories?post=12477"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/tags?post=12477"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}