{"id":12666,"date":"2026-06-04T12:59:08","date_gmt":"2026-06-04T12:59:08","guid":{"rendered":"https:\/\/www.vedprep.com\/exams\/?p=12666"},"modified":"2026-06-04T13:02:45","modified_gmt":"2026-06-04T13:02:45","slug":"catalysis-iit-jam","status":"publish","type":"post","link":"https:\/\/www.vedprep.com\/exams\/iit-jam\/catalysis-iit-jam\/","title":{"rendered":"Catalysis (Hydrogenation, Hydroformylation): IIT JAM 2027"},"content":{"rendered":"<p><strong>Catalysis<\/strong> (Hydrogenation, Hydroformylation) For IIT JAM focuses on the mechanisms and applications of organometallic reactions, specifically hydrogenation and hydroformylation, for competitive exams like IIT JAM.<\/p>\n<h2><strong>Syllabus: IIT JAM Organic Chemistry<\/strong><\/h2>\n<p data-path-to-node=\"1\">Preparing for <a href=\"https:\/\/jam2026.iitb.ac.in\/files\/syllabus_CY.pdf\" rel=\"nofollow noopener\" target=\"_blank\"><strong>IIT JAM Organic Chemistry<\/strong><\/a> can feel like a marathon, especially when you hit Unit 14.3. This is where organometallic reactions and <b data-path-to-node=\"1\" data-index-in-node=\"144\">catalysis<\/b> take center stage. If you are eyeing CSIR NET, GATE, or CUET PG down the road, mastering this topic right now will save you a ton of stress later.<\/p>\n<p data-path-to-node=\"2\">If you want to dive deep into the textbook theory, classics like <i data-path-to-node=\"2\" data-index-in-node=\"65\">Organic Chemistry<\/i> by Paula Yurkanis and <i data-path-to-node=\"2\" data-index-in-node=\"105\">Organic Chemistry<\/i> by Jerry March are your go-to resources. They give you a solid foundation, but today we are going to break these concepts down into plain, simple English.<\/p>\n<p data-path-to-node=\"3\">Organometallic <b data-path-to-node=\"3\" data-index-in-node=\"15\">catalysis<\/b> sounds intimidating, but it is just about using metal complexes to speed up chemical reactions. Two major players you need to know inside out for your exams are hydrogenation and hydroformylation. Let\u2019s make sense of them together.<\/p>\n<h2><strong>Catalysis (Hydrogenation, Hydroformylation) For IIT JAM: An Overview<\/strong><\/h2>\n<p>Think of <b data-path-to-node=\"6\" data-index-in-node=\"9\">catalysis<\/b> as a shortcut on a map. A catalyst lowers the activation energy barrier, helping a reaction happen way faster without getting used up in the process. You can hang out with two types: homogeneous catalysts (which sit in the same phase as your reactants, like a liquid dissolved in a liquid) and heterogeneous catalysts (which are in a different phase, like a solid metal sheet sitting in a liquid solution).<\/p>\n<p><img loading=\"lazy\" fetchpriority=\"high\" decoding=\"async\" class=\"alignnone size-medium wp-image-20811 aligncenter\" src=\"https:\/\/www.vedprep.com\/exams\/wp-content\/uploads\/Catalysis-294x300.png\" alt=\"Catalysis\" width=\"294\" height=\"300\" srcset=\"https:\/\/www.vedprep.com\/exams\/wp-content\/uploads\/Catalysis-294x300.png 294w, https:\/\/www.vedprep.com\/exams\/wp-content\/uploads\/Catalysis.png 670w\" sizes=\"(max-width: 294px) 100vw, 294px\" \/><\/p>\n<div class=\"attachment-container search-images\">\n<p data-path-to-node=\"8\">Hydrogenation is all about adding hydrogen (<span class=\"math-inline\" data-math=\"H_2\" data-index-in-node=\"44\">H<sub>2<\/sub><\/span>) across a double or triple bond, which we use to turn alkenes into alkanes. Hydroformylation is a slightly different beast\u2014it takes an alkene, mixes it with carbon monoxide (<span class=\"math-inline\" data-math=\"CO\" data-index-in-node=\"222\">CO<\/span>) and hydrogen (<span class=\"math-inline\" data-math=\"H_2\" data-index-in-node=\"240\">H<sub>2<\/sub><\/span>), and spits out an aldehyde.<\/p>\n<p data-path-to-node=\"9\">The secret sauce in these reactions is the transition metal catalyst. For classical hydrogenation, you will often see heterogeneous setups like Raney nickel or palladium on carbon (Pd\/C). For hydroformylation, the industry loves homogenous rhodium and platinum complexes.<\/p>\n<\/div>\n<h2><strong>Mechanism of Hydrogenation and Hydroformylation Reactions<\/strong><\/h2>\n<p data-path-to-node=\"12\">Let\u2019s look under the hood. Heterogeneous hydrogenation happens right on the surface of the metal.<\/p>\n<ol start=\"1\" data-path-to-node=\"13\">\n<li>\n<p data-path-to-node=\"13,0,0\">First, the unsaturated alkene grabs onto the catalyst surface (adsorption).<\/p>\n<\/li>\n<li>\n<p data-path-to-node=\"13,1,0\">Hydrogen (H\u2082)\u00a0binds to the metal center.<\/p>\n<\/li>\n<li>\n<p data-path-to-node=\"13,2,0\">The metal breaks the <span class=\"math-inline\" data-math=\"H\" data-index-in-node=\"21\">H<\/span>\u2013<span class=\"math-inline\" data-math=\"H\" data-index-in-node=\"23\">H<\/span>\u00a0bond and clips both hydrogens to itself (oxidative addition).<\/p>\n<\/li>\n<li>\n<p data-path-to-node=\"13,3,0\">The alkene shifts over and hooks onto one of those hydrogens (migratory insertion).<\/p>\n<\/li>\n<li>\n<p data-path-to-node=\"13,4,0\">The final product lets go of the metal completely (reductive elimination), leaving you with a clean, saturated alkane.<\/p>\n<\/li>\n<\/ol>\n<p data-path-to-node=\"14\">Hydroformylation\u2014often called the Oxo process\u2014relies heavily on rhodium or cobalt complexes. Here, the catalyst coordinates with <span class=\"math-inline\" data-math=\"CO\" data-index-in-node=\"129\">CO<\/span>\u00a0and <span class=\"math-inline\" data-math=\"H_2\" data-index-in-node=\"136\">H<sub>2<\/sub><\/span>\u00a0to insert a formyl group (<span class=\"math-inline\" data-math=\"-CHO\" data-index-in-node=\"166\">-CHO<\/span>) right onto the alkene chain.<\/p>\n<p data-path-to-node=\"15\">We cannot talk about these transition metals without talking about ligands. Ligands are the molecular sidekicks that bind to the metal center. By changing how bulky or electron-rich a ligand is, you can completely change how a catalyst behaves. At <a href=\"https:\/\/www.vedprep.com\/online-courses\"><strong>VedPrep<\/strong><\/a>, we often tell students to think of ligands as tuning knobs on a radio; tweak them correctly, and you get the exact reaction speed and selectivity you want.<\/p>\n<h2><strong>Worked Example: Hydrogenation Reaction of Alkenes<\/strong><\/h2>\n<p data-path-to-node=\"18\">Let\u2019s look at a classic question type that pops up in competitive exams.<\/p>\n<p data-path-to-node=\"18\"><b data-path-to-node=\"19,0\" data-index-in-node=\"0\">Question:<\/b> What is the product of the hydrogenation reaction of 2-butene in the presence of a palladium catalyst? Walk through the mechanism.<\/p>\n<p data-path-to-node=\"20\"><b data-path-to-node=\"20\" data-index-in-node=\"0\">Answer:<\/b> The reaction turns 2-butene into butane. Because it uses a solid palladium catalyst, this happens via a surface-mediated pathway.<\/p>\n<ul data-path-to-node=\"21\">\n<li>\n<p data-path-to-node=\"21,0,0\"><b data-path-to-node=\"21,0,0\" data-index-in-node=\"0\">Step 1:<\/b> Both 2-butene and <span class=\"math-inline\" data-math=\"H_2\" data-index-in-node=\"26\">H2<\/span>\u00a0stick to the Pd surface.<\/p>\n<\/li>\n<li>\n<p data-path-to-node=\"21,1,0\"><b data-path-to-node=\"21,1,0\" data-index-in-node=\"0\">Step 2:<\/b> Hydrogen steps over to the 2-butene molecule, creating a temporary alkyl intermediate bound to the metal.<\/p>\n<\/li>\n<li>\n<p data-path-to-node=\"21,2,0\"><b data-path-to-node=\"21,2,0\" data-index-in-node=\"0\">Step 3:<\/b> The remaining hydrogen snaps into place, and the brand-new butane molecule breaks free from the surface.<\/p>\n<\/li>\n<\/ul>\n<h2 data-path-to-node=\"24\"><strong>Misconception: Hydrogenation vs Hydroformylation Reactions<\/strong><\/h2>\n<p data-path-to-node=\"25\">A common trap for IIT JAM aspirants is mixing up what these two reactions actually add to a molecule.<\/p>\n<ul data-path-to-node=\"26\">\n<li>\n<p data-path-to-node=\"26,0,0\"><b data-path-to-node=\"26,0,0\" data-index-in-node=\"0\">The Trap:<\/b> Assuming both reactions just break double bonds and add simple groups.<\/p>\n<\/li>\n<li>\n<p data-path-to-node=\"26,1,0\"><b data-path-to-node=\"26,1,0\" data-index-in-node=\"0\">The Reality:<\/b> Hydrogenation only adds hydrogen atoms (<span class=\"math-inline\" data-math=\"H\" data-index-in-node=\"53\">H<\/span>), turning an alkene into an alkane. Hydroformylation adds a carbon atom because it injects a whole formyl group (<span class=\"math-inline\" data-math=\"-CHO\" data-index-in-node=\"168\">-CHO<\/span>). If you start with a 3-carbon alkene in hydrogenation, you get a 3-carbon alkane. If you start with a 3-carbon alkene in hydroformylation, you end up with a 4-carbon aldehyde.<\/p>\n<\/li>\n<\/ul>\n<h2><strong>Real-World Application: Hydroformylation of Alkenes in Industrial Production<\/strong><\/h2>\n<p data-path-to-node=\"29\">To visualize how this works on a massive scale, imagine a fictional chemical plant called &#8220;AlchemCo.&#8221; Let&#8217;s say AlchemCo needs to make thousands of liters of butanal every day to sell to companies that manufacture flexible plastics and medicines.<\/p>\n<p data-path-to-node=\"30\">They can&#8217;t just wait around for regular chemical pathways to slowly build these chains. Instead, they pump propene, carbon monoxide, and hydrogen into a massive reactor under high pressures (10 to 50 bar) and blazing heat (80 to 150\u00b0C).<\/p>\n<p data-path-to-node=\"31\">Inside that reactor, a soluble rhodium organometallic catalyst goes to work, snapping the components together instantly. Without organometallic <b data-path-to-node=\"31\" data-index-in-node=\"144\">catalysis<\/b>, running a plant like our fictional AlchemCo would be way too expensive and wasteful to survive.<\/p>\n<h2><strong>Catalysis (Hydrogenation, Hydroformylation) For IIT JAM<\/strong><\/h2>\n<p data-path-to-node=\"34\">When you are mapping out your study schedule for the IIT JAM, make sure you dedicate quality time to both homogeneous and heterogeneous <b data-path-to-node=\"34\" data-index-in-node=\"136\">catalysis<\/b>.<\/p>\n<ul data-path-to-node=\"35\">\n<li>\n<p data-path-to-node=\"35,0,0\"><b data-path-to-node=\"35,0,0\" data-index-in-node=\"0\">Step 1:<\/b> Review reaction kinetics so you understand how catalysts change activation energy.<\/p>\n<\/li>\n<li>\n<p data-path-to-node=\"35,1,0\"><b data-path-to-node=\"35,1,0\" data-index-in-node=\"0\">Step 2:<\/b> Map out the catalytic cycles for both alkene hydrogenation and the Oxo process.<\/p>\n<\/li>\n<li>\n<p data-path-to-node=\"35,2,0\"><b data-path-to-node=\"35,2,0\" data-index-in-node=\"0\">Step 3:<\/b> Tackle past-year question papers to see exactly how examiners phrase these problems.<\/p>\n<\/li>\n<\/ul>\n<p data-path-to-node=\"36\">We understand how overwhelming it can feel to memorize dozens of cyclic mechanisms while managing your college semester exams. That is exactly why our team at <a href=\"https:\/\/www.vedprep.com\/online-courses\/iit-jam\"><strong>VedPrep<\/strong> <\/a>builds structured video lectures and targeted practice question banks\u2014to help break down complex organometallic steps into logical, manageable pieces so you can walk into the exam hall feeling confident.<\/p>\n<h2><strong>Lab Application: Synthesis of Aldehydes through Hydroformylation Reaction<\/strong><\/h2>\n<p data-path-to-node=\"39\">Away from giant industrial plants, hydroformylation is also a brilliant tool in small-scale research labs. When synthetic chemists are trying to build complex, multi-step molecules\u2014like a new medicinal compound\u2014they often use rhodium-based catalysts to add an aldehyde functional group with pinpoint precision.<\/p>\n<p data-path-to-node=\"40\">Because rhodium catalysts are highly active, researchers can run these reactions under relatively mild lab conditions. This high selectivity means fewer messy side-products to clean up during column chromatography at the end of the day. Mastering the logic behind these laboratory choices is a huge step toward acing your organic chemistry papers.<\/p>\n<h2 data-path-to-node=\"40\"><strong>Final Thoughts\u00a0<\/strong><\/h2>\n<p data-path-to-node=\"40\">At the end of the day, mastering <b data-path-to-node=\"1\" data-index-in-node=\"33\">catalysis<\/b> isn&#8217;t about memorizing every single transition metal on the periodic table; it&#8217;s about understanding how these molecular machines move electrons to make difficult reactions happen with ease. When you&#8217;re revising hydrogenation and hydroformylation for the IIT JAM, focus on the structural changes\u2014track where the carbons go, notice how the oxidation state of the metal flips, and pay attention to what the ligands are doing. It is a dense topic, but once you start seeing the underlying patterns in these catalytic cycles, the questions become highly scoring opportunities rather than exam-day hurdles.<\/p>\n<p data-path-to-node=\"40\">To know more in detail from our faculty, watch our YouTube video:<\/p>\n<p class=\"responsive-video-wrap clr\"><iframe title=\"Stereochemistry One Shot Revision \ud83d\ude31 | CSIR NET June\/July 2026 | Chemical Sciences | VedPrep CSIR NET\" width=\"1200\" height=\"675\" src=\"https:\/\/www.youtube.com\/embed\/mHKTu9v14ps?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" referrerpolicy=\"strict-origin-when-cross-origin\" allowfullscreen><\/iframe><\/p>\n<section>\n<h2><strong>Frequently Asked Questions<\/strong><\/h2>\n<\/section>\n<style>#sp-ea-20814 .spcollapsing { height: 0; overflow: hidden; transition-property: height;transition-duration: 300ms;}#sp-ea-20814.sp-easy-accordion>.sp-ea-single {margin-bottom: 10px; border: 1px solid #e2e2e2; }#sp-ea-20814.sp-easy-accordion>.sp-ea-single>.ea-header a {color: #444;}#sp-ea-20814.sp-easy-accordion>.sp-ea-single>.sp-collapse>.ea-body {background: #fff; color: #444;}#sp-ea-20814.sp-easy-accordion>.sp-ea-single {background: #eee;}#sp-ea-20814.sp-easy-accordion>.sp-ea-single>.ea-header a .ea-expand-icon { float: left; color: #444;font-size: 16px;}<\/style><div id=\"sp_easy_accordion-1780577173\">\n<div id=\"sp-ea-20814\" class=\"sp-ea-one sp-easy-accordion\" data-ea-active=\"ea-click\" data-ea-mode=\"vertical\" data-preloader=\"\" data-scroll-active-item=\"\" data-offset-to-scroll=\"0\">\n\n<!-- Start accordion card div. -->\n<div class=\"ea-card ea-expand sp-ea-single\">\n\t<!-- Start accordion header. -->\n\t<h3 class=\"ea-header\">\n\t\t<!-- Add anchor tag for header. -->\n\t\t<a class=\"collapsed\" id=\"ea-header-208140\" role=\"button\" data-sptoggle=\"spcollapse\" data-sptarget=\"#collapse208140\" aria-controls=\"collapse208140\" href=\"#\"  aria-expanded=\"true\" tabindex=\"0\">\n\t\t<i aria-hidden=\"true\" role=\"presentation\" class=\"ea-expand-icon eap-icon-ea-expand-minus\"><\/i> What is the main difference between homogeneous and heterogeneous catalysis?\t\t<\/a> <!-- Close anchor tag for header. -->\n\t<\/h3>\t<!-- Close header tag. -->\n\t<!-- Start collapsible content div. -->\n\t<div class=\"sp-collapse spcollapse collapsed show\" id=\"collapse208140\" data-parent=\"#sp-ea-20814\" role=\"region\" aria-labelledby=\"ea-header-208140\">  <!-- Content div. -->\n\t\t<div class=\"ea-body\">\n\t\t<p>It all comes down to the physical phase. In heterogeneous catalysis, the catalyst is in a different phase than the reactants\u2014usually a solid metal surface sitting in a liquid or gas mixture. In homogeneous catalysis, everything is mixed together in a single phase, like a soluble rhodium complex dissolved in the organic solvent with your alkene.<\/p>\n\t\t<\/div> <!-- Close content div. -->\n\t<\/div> <!-- Close collapse div. -->\n<\/div> <!-- Close card div. -->\n<!-- Start accordion card div. -->\n<div class=\"ea-card  sp-ea-single\">\n\t<!-- Start accordion header. -->\n\t<h3 class=\"ea-header\">\n\t\t<!-- Add anchor tag for header. -->\n\t\t<a class=\"collapsed\" id=\"ea-header-208141\" role=\"button\" data-sptoggle=\"spcollapse\" data-sptarget=\"#collapse208141\" aria-controls=\"collapse208141\" href=\"#\"  aria-expanded=\"false\" tabindex=\"0\">\n\t\t<i aria-hidden=\"true\" role=\"presentation\" class=\"ea-expand-icon eap-icon-ea-expand-plus\"><\/i> Why does hydroformylation increase the carbon chain length while hydrogenation doesn't?\t\t<\/a> <!-- Close anchor tag for header. -->\n\t<\/h3>\t<!-- Close header tag. -->\n\t<!-- Start collapsible content div. -->\n\t<div class=\"sp-collapse spcollapse \" id=\"collapse208141\" data-parent=\"#sp-ea-20814\" role=\"region\" aria-labelledby=\"ea-header-208141\">  <!-- Content div. -->\n\t\t<div class=\"ea-body\">\n\t\t<p>Hydrogenation simply adds <span class=\"math-inline\" data-math=\"H_2\" data-index-in-node=\"121\">H2<\/span> across the double bond, leaving the carbon skeleton alone. Hydroformylation (the Oxo process) introduces carbon monoxide (<span class=\"math-inline\" data-math=\"CO\" data-index-in-node=\"247\">CO<\/span>) along with <span class=\"math-inline\" data-math=\"H_2\" data-index-in-node=\"262\">H2<\/span>. That <span class=\"math-inline\" data-math=\"CO\" data-index-in-node=\"272\">CO<\/span>\u00a0gets inserted into the chain, adding a brand-new formyl carbon (<span class=\"math-inline\" data-math=\"-CHO\" data-index-in-node=\"339\">-CHO<\/span>) to your molecule.<\/p>\n\t\t<\/div> <!-- Close content div. -->\n\t<\/div> <!-- Close collapse div. -->\n<\/div> <!-- Close card div. -->\n<!-- Start accordion card div. -->\n<div class=\"ea-card  sp-ea-single\">\n\t<!-- Start accordion header. -->\n\t<h3 class=\"ea-header\">\n\t\t<!-- Add anchor tag for header. -->\n\t\t<a class=\"collapsed\" id=\"ea-header-208142\" role=\"button\" data-sptoggle=\"spcollapse\" data-sptarget=\"#collapse208142\" aria-controls=\"collapse208142\" href=\"#\"  aria-expanded=\"false\" tabindex=\"0\">\n\t\t<i aria-hidden=\"true\" role=\"presentation\" class=\"ea-expand-icon eap-icon-ea-expand-plus\"><\/i> What are the typical transition metals used in industrial hydroformylation?\t\t<\/a> <!-- Close anchor tag for header. -->\n\t<\/h3>\t<!-- Close header tag. -->\n\t<!-- Start collapsible content div. -->\n\t<div class=\"sp-collapse spcollapse \" id=\"collapse208142\" data-parent=\"#sp-ea-20814\" role=\"region\" aria-labelledby=\"ea-header-208142\">  <!-- Content div. -->\n\t\t<div class=\"ea-body\">\n\t\t<p>Cobalt (<span class=\"math-inline\" data-math=\"Co\" data-index-in-node=\"91\">Co<\/span>) and Rhodium (<span class=\"math-inline\" data-math=\"Rh\" data-index-in-node=\"108\">Rh<\/span>) are the absolute superstars here. While cobalt was the historical favorite, modern industrial setups prefer rhodium because it operates under much milder pressures and temperatures and offers better selectivity.<\/p>\n\t\t<\/div> <!-- Close content div. -->\n\t<\/div> <!-- Close collapse div. -->\n<\/div> <!-- Close card div. -->\n<!-- Start accordion card div. -->\n<div class=\"ea-card  sp-ea-single\">\n\t<!-- Start accordion header. -->\n\t<h3 class=\"ea-header\">\n\t\t<!-- Add anchor tag for header. -->\n\t\t<a class=\"collapsed\" id=\"ea-header-208143\" role=\"button\" data-sptoggle=\"spcollapse\" data-sptarget=\"#collapse208143\" aria-controls=\"collapse208143\" href=\"#\"  aria-expanded=\"false\" tabindex=\"0\">\n\t\t<i aria-hidden=\"true\" role=\"presentation\" class=\"ea-expand-icon eap-icon-ea-expand-plus\"><\/i> What role do ligands play in homogeneous catalysts?\t\t<\/a> <!-- Close anchor tag for header. -->\n\t<\/h3>\t<!-- Close header tag. -->\n\t<!-- Start collapsible content div. -->\n\t<div class=\"sp-collapse spcollapse \" id=\"collapse208143\" data-parent=\"#sp-ea-20814\" role=\"region\" aria-labelledby=\"ea-header-208143\">  <!-- Content div. -->\n\t\t<div class=\"ea-body\">\n\t\t<p>Think of ligands as the control switches of the metal center. By changing their steric bulk (how much space they take up) or electronic properties (how much electron density they donate), you can tune the catalyst to make the reaction faster, safer, or more selective for a specific product.<\/p>\n\t\t<\/div> <!-- Close content div. -->\n\t<\/div> <!-- Close collapse div. -->\n<\/div> <!-- Close card div. -->\n<!-- Start accordion card div. -->\n<div class=\"ea-card  sp-ea-single\">\n\t<!-- Start accordion header. -->\n\t<h3 class=\"ea-header\">\n\t\t<!-- Add anchor tag for header. -->\n\t\t<a class=\"collapsed\" id=\"ea-header-208144\" role=\"button\" data-sptoggle=\"spcollapse\" data-sptarget=\"#collapse208144\" aria-controls=\"collapse208144\" href=\"#\"  aria-expanded=\"false\" tabindex=\"0\">\n\t\t<i aria-hidden=\"true\" role=\"presentation\" class=\"ea-expand-icon eap-icon-ea-expand-plus\"><\/i> What is 'oxidative addition' in a catalytic cycle?\t\t<\/a> <!-- Close anchor tag for header. -->\n\t<\/h3>\t<!-- Close header tag. -->\n\t<!-- Start collapsible content div. -->\n\t<div class=\"sp-collapse spcollapse \" id=\"collapse208144\" data-parent=\"#sp-ea-20814\" role=\"region\" aria-labelledby=\"ea-header-208144\">  <!-- Content div. -->\n\t\t<div class=\"ea-body\">\n\t\t<p>This is the step where the metal center breaks a bond in a reactant molecule (like the <span class=\"math-inline\" data-math=\"H-H\" data-index-in-node=\"145\">H-H<\/span> bond in H\u2082)\u00a0and attaches both pieces to itself. In the process, the metal's formal oxidation state increases by +2. It's essentially the metal \"gearing up\" for the reaction.<\/p>\n\t\t<\/div> <!-- Close content div. -->\n\t<\/div> <!-- Close collapse div. -->\n<\/div> <!-- Close card div. -->\n<!-- Start accordion card div. -->\n<div class=\"ea-card  sp-ea-single\">\n\t<!-- Start accordion header. -->\n\t<h3 class=\"ea-header\">\n\t\t<!-- Add anchor tag for header. -->\n\t\t<a class=\"collapsed\" id=\"ea-header-208145\" role=\"button\" data-sptoggle=\"spcollapse\" data-sptarget=\"#collapse208145\" aria-controls=\"collapse208145\" href=\"#\"  aria-expanded=\"false\" tabindex=\"0\">\n\t\t<i aria-hidden=\"true\" role=\"presentation\" class=\"ea-expand-icon eap-icon-ea-expand-plus\"><\/i> What happens during 'migratory insertion'?\t\t<\/a> <!-- Close anchor tag for header. -->\n\t<\/h3>\t<!-- Close header tag. -->\n\t<!-- Start collapsible content div. -->\n\t<div class=\"sp-collapse spcollapse \" id=\"collapse208145\" data-parent=\"#sp-ea-20814\" role=\"region\" aria-labelledby=\"ea-header-208145\">  <!-- Content div. -->\n\t\t<div class=\"ea-body\">\n\t\t<p>In this step, a ligand that is already bound to the metal (like an alkene) shifts and inserts itself into an adjacent metal-ligand bond (like a metal-hydride bond). This is the crucial moment where the new carbon-hydrogen or carbon-carbon bond actually forms.<\/p>\n\t\t<\/div> <!-- Close content div. -->\n\t<\/div> <!-- Close collapse div. -->\n<\/div> <!-- Close card div. -->\n<!-- Start accordion card div. -->\n<div class=\"ea-card  sp-ea-single\">\n\t<!-- Start accordion header. -->\n\t<h3 class=\"ea-header\">\n\t\t<!-- Add anchor tag for header. -->\n\t\t<a class=\"collapsed\" id=\"ea-header-208146\" role=\"button\" data-sptoggle=\"spcollapse\" data-sptarget=\"#collapse208146\" aria-controls=\"collapse208146\" href=\"#\"  aria-expanded=\"false\" tabindex=\"0\">\n\t\t<i aria-hidden=\"true\" role=\"presentation\" class=\"ea-expand-icon eap-icon-ea-expand-plus\"><\/i> How does 'reductive elimination' close the catalytic loop?\t\t<\/a> <!-- Close anchor tag for header. -->\n\t<\/h3>\t<!-- Close header tag. -->\n\t<!-- Start collapsible content div. -->\n\t<div class=\"sp-collapse spcollapse \" id=\"collapse208146\" data-parent=\"#sp-ea-20814\" role=\"region\" aria-labelledby=\"ea-header-208146\">  <!-- Content div. -->\n\t\t<div class=\"ea-body\">\n\t\t<p>It\u2019s the exact opposite of oxidative addition. Two ligands bound to the metal center couple together and break free as the final product. This drops the metal's oxidation state back down by -2, regenerating the original catalyst so it can start the cycle all over again.<\/p>\n\t\t<\/div> <!-- Close content div. -->\n\t<\/div> <!-- Close collapse div. -->\n<\/div> <!-- Close card div. -->\n<!-- Start accordion card div. -->\n<div class=\"ea-card  sp-ea-single\">\n\t<!-- Start accordion header. -->\n\t<h3 class=\"ea-header\">\n\t\t<!-- Add anchor tag for header. -->\n\t\t<a class=\"collapsed\" id=\"ea-header-208147\" role=\"button\" data-sptoggle=\"spcollapse\" data-sptarget=\"#collapse208147\" aria-controls=\"collapse208147\" href=\"#\"  aria-expanded=\"false\" tabindex=\"0\">\n\t\t<i aria-hidden=\"true\" role=\"presentation\" class=\"ea-expand-icon eap-icon-ea-expand-plus\"><\/i> Why is Raney nickel pyrophoric, and how does it relate to hydrogenation?\t\t<\/a> <!-- Close anchor tag for header. -->\n\t<\/h3>\t<!-- Close header tag. -->\n\t<!-- Start collapsible content div. -->\n\t<div class=\"sp-collapse spcollapse \" id=\"collapse208147\" data-parent=\"#sp-ea-20814\" role=\"region\" aria-labelledby=\"ea-header-208147\">  <!-- Content div. -->\n\t\t<div class=\"ea-body\">\n\t\t<p>Raney nickel is a fine-grained solid alloy that is absolutely packed with adsorbed hydrogen. Because of its massive surface area and high hydrogen content, it can spontaneously ignite when exposed to air. It\u2019s used as a highly active heterogeneous catalyst to speed up the hydrogenation of double bonds, aromatic rings, and functional groups.<\/p>\n\t\t<\/div> <!-- Close content div. -->\n\t<\/div> <!-- Close collapse div. -->\n<\/div> <!-- Close card div. -->\n<!-- Start accordion card div. -->\n<div class=\"ea-card  sp-ea-single\">\n\t<!-- Start accordion header. -->\n\t<h3 class=\"ea-header\">\n\t\t<!-- Add anchor tag for header. -->\n\t\t<a class=\"collapsed\" id=\"ea-header-208148\" role=\"button\" data-sptoggle=\"spcollapse\" data-sptarget=\"#collapse208148\" aria-controls=\"collapse208148\" href=\"#\"  aria-expanded=\"false\" tabindex=\"0\">\n\t\t<i aria-hidden=\"true\" role=\"presentation\" class=\"ea-expand-icon eap-icon-ea-expand-plus\"><\/i> Can hydroformylation yield both linear and branched aldehydes?\t\t<\/a> <!-- Close anchor tag for header. -->\n\t<\/h3>\t<!-- Close header tag. -->\n\t<!-- Start collapsible content div. -->\n\t<div class=\"sp-collapse spcollapse \" id=\"collapse208148\" data-parent=\"#sp-ea-20814\" role=\"region\" aria-labelledby=\"ea-header-208148\">  <!-- Content div. -->\n\t\t<div class=\"ea-body\">\n\t\t<p>Yes, and this is a classic exam talking point! When the formyl group adds to an unsymmetrical alkene, it can land on the terminal carbon (giving a linear product) or the internal carbon (giving a branched product). Industries generally prefer the linear aldehyde, which is why ligand tuning is so important to favor that specific outcome.<\/p>\n\t\t<\/div> <!-- Close content div. -->\n\t<\/div> <!-- Close collapse div. -->\n<\/div> <!-- Close card div. -->\n<!-- Start accordion card div. -->\n<div class=\"ea-card  sp-ea-single\">\n\t<!-- Start accordion header. -->\n\t<h3 class=\"ea-header\">\n\t\t<!-- Add anchor tag for header. -->\n\t\t<a class=\"collapsed\" id=\"ea-header-208149\" role=\"button\" data-sptoggle=\"spcollapse\" data-sptarget=\"#collapse208149\" aria-controls=\"collapse208149\" href=\"#\"  aria-expanded=\"false\" tabindex=\"0\">\n\t\t<i aria-hidden=\"true\" role=\"presentation\" class=\"ea-expand-icon eap-icon-ea-expand-plus\"><\/i> What is the oxidation state of rhodium in active hydroformylation catalytic species?\t\t<\/a> <!-- Close anchor tag for header. -->\n\t<\/h3>\t<!-- Close header tag. -->\n\t<!-- Start collapsible content div. -->\n\t<div class=\"sp-collapse spcollapse \" id=\"collapse208149\" data-parent=\"#sp-ea-20814\" role=\"region\" aria-labelledby=\"ea-header-208149\">  <!-- Content div. -->\n\t\t<div class=\"ea-body\">\n\t\t<p>In active catalytic cycles for hydroformylation, such as when using <span class=\"math-inline\" data-math=\"HCo(CO)_4\" data-index-in-node=\"161\">HCo(CO)4<\/span> or HRh(CO)(PPh\u2083)\u2083,\u00a0the transition metal typically rests in a +1 oxidation state before going through the cyclic addition steps.<\/p>\n\t\t<\/div> <!-- Close content div. -->\n\t<\/div> <!-- Close collapse div. -->\n<\/div> <!-- Close card div. -->\n<!-- Start accordion card div. -->\n<div class=\"ea-card  sp-ea-single\">\n\t<!-- Start accordion header. -->\n\t<h3 class=\"ea-header\">\n\t\t<!-- Add anchor tag for header. -->\n\t\t<a class=\"collapsed\" id=\"ea-header-2081410\" role=\"button\" data-sptoggle=\"spcollapse\" data-sptarget=\"#collapse2081410\" aria-controls=\"collapse2081410\" href=\"#\"  aria-expanded=\"false\" tabindex=\"0\">\n\t\t<i aria-hidden=\"true\" role=\"presentation\" class=\"ea-expand-icon eap-icon-ea-expand-plus\"><\/i> How do you distinguish between a reactant and a catalyst in a written question?\t\t<\/a> <!-- Close anchor tag for header. -->\n\t<\/h3>\t<!-- Close header tag. -->\n\t<!-- Start collapsible content div. -->\n\t<div class=\"sp-collapse spcollapse \" id=\"collapse2081410\" data-parent=\"#sp-ea-20814\" role=\"region\" aria-labelledby=\"ea-header-2081410\">  <!-- Content div. -->\n\t\t<div class=\"ea-body\">\n\t\t<p>Look at where it ends up. If a metal complex or substance is written over the reaction arrow and emerges completely unchanged at the end of the chemical equation, it's a catalyst. If its atoms are permanently incorporated into the final molecular structure, it's a reactant.<\/p>\n\t\t<\/div> <!-- Close content div. -->\n\t<\/div> <!-- Close collapse div. -->\n<\/div> <!-- Close card div. -->\n<!-- Start accordion card div. -->\n<div class=\"ea-card  sp-ea-single\">\n\t<!-- Start accordion header. -->\n\t<h3 class=\"ea-header\">\n\t\t<!-- Add anchor tag for header. -->\n\t\t<a class=\"collapsed\" id=\"ea-header-2081411\" role=\"button\" data-sptoggle=\"spcollapse\" data-sptarget=\"#collapse2081411\" aria-controls=\"collapse2081411\" href=\"#\"  aria-expanded=\"false\" tabindex=\"0\">\n\t\t<i aria-hidden=\"true\" role=\"presentation\" class=\"ea-expand-icon eap-icon-ea-expand-plus\"><\/i> Does hydrogenation change the stereochemistry of an alkene?\t\t<\/a> <!-- Close anchor tag for header. -->\n\t<\/h3>\t<!-- Close header tag. -->\n\t<!-- Start collapsible content div. -->\n\t<div class=\"sp-collapse spcollapse \" id=\"collapse2081411\" data-parent=\"#sp-ea-20814\" role=\"region\" aria-labelledby=\"ea-header-2081411\">  <!-- Content div. -->\n\t\t<div class=\"ea-body\">\n\t\t<p>Absolutely. Heterogeneous hydrogenation on a metal surface typically delivers both hydrogen atoms from the <i data-path-to-node=\"14\" data-index-in-node=\"175\">same side<\/i> of the flat double bond. This results in <b data-path-to-node=\"14\" data-index-in-node=\"226\">syn-addition<\/b>, which completely dictates whether you get a <i data-path-to-node=\"14\" data-index-in-node=\"284\">cis<\/i> or <i data-path-to-node=\"14\" data-index-in-node=\"291\">trans<\/i> derivative if chiral centers are created.<\/p>\n\t\t<\/div> <!-- Close content div. -->\n\t<\/div> <!-- Close collapse div. -->\n<\/div> <!-- Close card div. -->\n<!-- Start accordion card div. -->\n<div class=\"ea-card  sp-ea-single\">\n\t<!-- Start accordion header. -->\n\t<h3 class=\"ea-header\">\n\t\t<!-- Add anchor tag for header. -->\n\t\t<a class=\"collapsed\" id=\"ea-header-2081412\" role=\"button\" data-sptoggle=\"spcollapse\" data-sptarget=\"#collapse2081412\" aria-controls=\"collapse2081412\" href=\"#\"  aria-expanded=\"false\" tabindex=\"0\">\n\t\t<i aria-hidden=\"true\" role=\"presentation\" class=\"ea-expand-icon eap-icon-ea-expand-plus\"><\/i> Why can't we use simple transition metals instead of complex organometallic coordination compounds?\t\t<\/a> <!-- Close anchor tag for header. -->\n\t<\/h3>\t<!-- Close header tag. -->\n\t<!-- Start collapsible content div. -->\n\t<div class=\"sp-collapse spcollapse \" id=\"collapse2081412\" data-parent=\"#sp-ea-20814\" role=\"region\" aria-labelledby=\"ea-header-2081412\">  <!-- Content div. -->\n\t\t<div class=\"ea-body\">\n\t\t<p>Pure transition metals work great for heterogeneous surfaces (like a sheet of Platinum), but they aren't soluble in organic reaction flasks. By wrapping the metal in organic ligands, we make it highly soluble in solvents, allowing us to perform precise, homogeneous chemistry right in the solution.<\/p>\n\t\t<\/div> <!-- Close content div. -->\n\t<\/div> <!-- Close collapse div. -->\n<\/div> <!-- Close card div. -->\n<!-- Start accordion card div. -->\n<div class=\"ea-card  sp-ea-single\">\n\t<!-- Start accordion header. -->\n\t<h3 class=\"ea-header\">\n\t\t<!-- Add anchor tag for header. -->\n\t\t<a class=\"collapsed\" id=\"ea-header-2081413\" role=\"button\" data-sptoggle=\"spcollapse\" data-sptarget=\"#collapse2081413\" aria-controls=\"collapse2081413\" href=\"#\"  aria-expanded=\"false\" tabindex=\"0\">\n\t\t<i aria-hidden=\"true\" role=\"presentation\" class=\"ea-expand-icon eap-icon-ea-expand-plus\"><\/i> How can I avoid counting errors in hydroformylation exam problems?\t\t<\/a> <!-- Close anchor tag for header. -->\n\t<\/h3>\t<!-- Close header tag. -->\n\t<!-- Start collapsible content div. -->\n\t<div class=\"sp-collapse spcollapse \" id=\"collapse2081413\" data-parent=\"#sp-ea-20814\" role=\"region\" aria-labelledby=\"ea-header-2081413\">  <!-- Content div. -->\n\t\t<div class=\"ea-body\">\n\t\t<p>We always emphasize this at VedPrep: draw your starting alkene and literally map out a new single bond connecting to a <span class=\"math-inline\" data-math=\"-CHO\" data-index-in-node=\"194\">-CHO<\/span>\u00a0group. Count your total carbons before and after. If your reactant has <span class=\"math-inline\" data-math=\"n\" data-index-in-node=\"270\">$n$<\/span> carbons, your product <i data-path-to-node=\"16\" data-index-in-node=\"294\">must<\/i> have <span class=\"math-inline\" data-math=\"n+1\" data-index-in-node=\"304\">$n+1$<\/span> carbons.<\/p>\n\t\t<\/div> <!-- Close content div. -->\n\t<\/div> <!-- Close collapse div. -->\n<\/div> <!-- Close card div. -->\n<\/div>\n<\/div>\n\n","protected":false},"excerpt":{"rendered":"<p>Catalysis (Hydrogenation, Hydroformylation) For IIT JAM focuses on the mechanisms and applications of organometallic reactions, specifically hydrogenation and hydroformylation, for competitive exams like IIT JAM. This topic is crucial for IIT JAM Organic Chemistry and is relevant to CSIR NET and GATE exam preparations, as well as CUET PG aspirants.<\/p>\n","protected":false},"author":11,"featured_media":12665,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"footnotes":"","rank_math_seo_score":85},"categories":[23],"tags":[17017,2923,17018,17019,17020,17021,2922],"class_list":["post-12666","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-iit-jam","tag-catalysis-hydrogenation","tag-competitive-exams","tag-hydroformylation-for-iit-jam","tag-hydroformylation-for-iit-jam-notes","tag-hydroformylation-for-iit-jam-questions","tag-hydroformylation-for-iit-jam-study-material","tag-vedprep","entry","has-media"],"acf":[],"_links":{"self":[{"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/posts\/12666","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/users\/11"}],"replies":[{"embeddable":true,"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/comments?post=12666"}],"version-history":[{"count":4,"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/posts\/12666\/revisions"}],"predecessor-version":[{"id":20815,"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/posts\/12666\/revisions\/20815"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/media\/12665"}],"wp:attachment":[{"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/media?parent=12666"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/categories?post=12666"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/tags?post=12666"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}