{"id":21581,"date":"2026-07-30T01:33:56","date_gmt":"2026-07-30T01:33:56","guid":{"rendered":"https:\/\/www.vedprep.com\/exams\/?p=21581"},"modified":"2026-07-30T01:33:56","modified_gmt":"2026-07-30T01:33:56","slug":"factors-affecting-crystal-field-stabilization-ener","status":"publish","type":"post","link":"https:\/\/www.vedprep.com\/exams\/uppsc\/factors-affecting-crystal-field-stabilization-ener\/","title":{"rendered":"Factors Affecting Crystal Field Stabilization Energy Cfse"},"content":{"rendered":"<article>\n<h1>Top 5 Critical Factors Affecting Crystal Field Stabilization Energy (CFSE)<\/h1>\n<p>The <strong>critical factors affecting crystal field stabilization energy<\/strong> are essential for understanding the stability of transition metal complexes\u2014a cornerstone topic for UPPSC Assistant Professor exams. Mastering these factors will not only boost your scores in inorganic chemistry but also deepen your grasp of coordination compounds, a key area in competitive exams like CSIR NET, IIT JAM, and GATE.<\/strong><\/p>\n<p>In this guide, we break down the <strong>critical factors affecting crystal field stabilization energy<\/strong> with clear explanations, practical examples, and exam-focused strategies. Whether you&#8217;re preparing for UPPSC or other advanced exams, this breakdown will help you confidently tackle questions related to <strong>critical factors affecting crystal field stabilization energy<\/strong>.<\/p>\n<h2>Factors Affecting Crystal Field Stabilization Energy Cfse: Key Concepts<\/h2>\n<p>Crystal Field Stabilization Energy (CFSE) is a fundamental concept in inorganic chemistry that explains how ligands interact with the d-orbitals of a central metal ion. The <strong>critical factors affecting crystal field stabilization energy<\/strong> determine the stability of these complexes, influencing their reactivity, color, and magnetic properties. For UPPSC Assistant Professor aspirants, understanding these factors is crucial for solving numerical problems and explaining experimental observations.<\/p>\n<p>Understanding Factors affecting Crystal Field Stabilization Energy CFSE thoroughly is essential for tackling related exam questions with confidence.<\/p>\n<p>In this section, we explore how <strong>critical factors affecting crystal field stabilization energy<\/strong> influence the energy levels of d-orbitals and the overall stability of metal complexes. These factors include:<\/p>\n<ul>\n<li>Ligand field strength<\/li>\n<li>Coordination number and geometry<\/li>\n<li>Crystal field splitting energy (\u0394)<\/li>\n<li>Oxidation state of the metal ion<\/li>\n<li>Electronic configuration of the metal ion<\/li>\n<\/ul>\n<p>Each of these factors plays a distinct role in determining the <strong>critical factors affecting crystal field stabilization energy<\/strong>, and we\u2019ll delve into each one with detailed explanations and examples.<\/p>\n<p>Many aspirants underestimate how often Factors affecting Crystal Field Stabilization Energy CFSE appears across different question formats in these exams.<\/p>\n<h2>Factor 1: Ligand Field Strength \u2013 The Heart of <strong>Critical Factors Affecting Crystal Field Stabilization Energy<\/strong><\/h2>\n<p>The <strong>critical factors affecting crystal field stabilization energy<\/strong> begin with the nature of the ligands. Ligands are classified based on their field strength, which directly impacts the splitting of d-orbitals. Strong-field ligands, such as <code>CN^-<\/code>, <code>CO<\/code>, and <code>NO_2^-<\/code>, cause a larger splitting of d-orbitals, leading to higher CFSE values. Conversely, weak-field ligands like <code>I^-<\/code>, <code>Br^-<\/code>, and <code>H_2O<\/code> result in smaller splitting and lower CFSE.<\/p>\n<p>The <strong>critical factors affecting crystal field stabilization energy<\/strong> are heavily influenced by the spectrochemical series, which ranks ligands from weakest to strongest field strength. For instance:<\/p>\n<p>A solid grasp of Factors affecting Crystal Field Stabilization Energy CFSE also helps when questions combine multiple topics in a single problem.<\/p>\n<ul>\n<li><strong>Weak-field ligands:<\/strong> <code>I^-<\/code> &lt; <code>Br^-<\/code> &lt; <code>Cl^-<\/code> &lt; <code>F^-<\/code> &lt; <code>H_2O<\/code><\/li>\n<li><strong>Strong-field ligands:<\/strong> <code>NH_3<\/code> &lt; <code>en<\/code> &lt; <code>CN^-<\/code> &lt; <code>CO<\/code><\/li>\n<\/ul>\n<p>Understanding the <strong>critical factors affecting crystal field stabilization energy<\/strong> allows you to predict the stability and magnetic properties of complexes. For example, <code>[Fe(CN)_6]^{4-}<\/code> has a higher CFSE compared to <code>[Fe(H_2O)_6]^{2+}<\/code> due to the stronger field strength of <code>CN^-<\/code> ligands.<\/p>\n<h2>Factor 2: Coordination Number and Geometry \u2013 Shaping the <strong>Critical Factors Affecting Crystal Field Stabilization Energy<\/strong><\/h2>\n<p>The coordination number, or the number of ligands attached to the central metal ion, is another <strong>critical factor affecting crystal field stabilization energy<\/strong>. Different geometries\u2014such as octahedral, tetrahedral, and square planar\u2014result in varying CFSE values due to differences in ligand field strength and orbital splitting.<\/p>\n<p>Revisiting Factors affecting Crystal Field Stabilization Energy CFSE periodically, rather than cramming once, tends to improve long-term retention.<\/p>\n<p>For instance:<\/p>\n<ul>\n<li><strong>Octahedral complexes (CN = 6):<\/strong> Exhibit the highest CFSE among common geometries due to strong ligand field interactions.<\/li>\n<li><strong>Tetrahedral complexes (CN = 4):<\/strong> Show lower CFSE compared to octahedral complexes because the ligand field is weaker.<\/li>\n<li><strong>Square planar complexes (CN = 4):<\/strong> Often exhibit high CFSE, particularly with strong-field ligands like <code>CN^-<\/code>.<\/li>\n<\/ul>\n<p>In the context of <strong>critical factors affecting crystal field stabilization energy<\/strong>, the geometry of the complex dictates how the d-orbitals split. For example, an octahedral complex like <code>[Co(NH_3)_6]^{3+}<\/code> will have a higher CFSE than a tetrahedral complex like <code>[ZnCl_4]^{2-}<\/code>.<\/p>\n<p>Exam setters frequently rephrase questions on Factors affecting Crystal Field Stabilization Energy CFSE, so understanding the underlying logic matters more than memorizing.<\/p>\n<h2>Factor 3: Crystal Field Splitting Energy (\u0394) \u2013 The Direct Driver of <strong>Critical Factors Affecting Crystal Field Stabilization Energy<\/strong><\/h2>\n<p>The crystal field splitting energy, denoted as \u0394 (or \u0394_o for octahedral complexes), is the energy difference between the <code>t_{2g}<\/code> and <code>e_g<\/code> orbitals. This is one of the most <strong>critical factors affecting crystal field stabilization energy<\/strong>, as it directly determines the magnitude of CFSE.<\/p>\n<p>A larger \u0394 results in a higher CFSE, increasing the stability of the complex. For example:<\/p>\n<p>Building a strong foundation in Factors affecting Crystal Field Stabilization Energy CFSE pays off across several related exam sections.<\/p>\n<ul>\n<li><code>[CoF_6]^{3-}<\/code> has a lower \u0394 and thus a lower CFSE compared to <code>[Co(NH_3)_6]^{3+}<\/code>.<\/li>\n<li><code>[Fe(CN)_6]^{4-}<\/code> exhibits a high \u0394 due to the strong-field <code>CN^-<\/code> ligands, leading to a significantly higher CFSE.<\/li>\n<\/ul>\n<p>The relationship between \u0394 and CFSE can be expressed mathematically. For an octahedral complex with a <code>d^6<\/code> configuration, the CFSE is calculated as:<\/p>\n<p><code>CFSE = 0.4 * \u0394_o + 1.6 * \u0394_o = 2.0 * \u0394_o<\/code><\/p>\n<p>Practicing varied problems on Factors affecting Crystal Field Stabilization Energy CFSE is one of the most efficient ways to prepare.<\/p>\n<p>This highlights why <strong>critical factors affecting crystal field stabilization energy<\/strong> like \u0394 are so vital in predicting complex stability.<\/p>\n<h2>Factor 4: Oxidation State of the Metal Ion \u2013 An Often Overlooked <strong>Critical Factor Affecting Crystal Field Stabilization Energy<\/strong><\/h2>\n<p>The oxidation state of the metal ion is another <strong>critical factor affecting crystal field stabilization energy<\/strong> that significantly influences CFSE. Higher oxidation states generally lead to stronger ligand field interactions, increasing \u0394 and, consequently, CFSE.<\/p>\n<p>Reviewing Factors affecting Crystal Field Stabilization Energy CFSE alongside solved examples makes the concept far easier to recall under exam pressure.<\/p>\n<p>For example:<\/p>\n<ul>\n<li><code>[Ti(H_2O)_6]^{3+}<\/code> (Ti<sup>3+<\/sup>) has a higher CFSE compared to <code>[Ti(H_2O)_6]^{2+}<\/code> (Ti<sup>2+<\/sup>) because the higher charge on the metal ion strengthens the interaction with ligands.<\/li>\n<li><code>[Co(NH_3)_6]^{3+}<\/code> exhibits a higher CFSE than <code>[Co(NH_3)_6]^{2+}<\/code> due to the increased charge on the cobalt ion.<\/li>\n<\/ul>\n<p>This factor underscores the importance of considering the metal ion\u2019s charge when analyzing <strong>critical factors affecting crystal field stabilization energy<\/strong>.<\/p>\n<p>Aspirants who consistently revise Factors affecting Crystal Field Stabilization Energy CFSE tend to perform better on application-based questions.<\/p>\n<h2>Factor 5: Electronic Configuration of the Metal Ion \u2013 The Final Piece of the <strong>Critical Factors Affecting Crystal Field Stabilization Energy<\/strong> Puzzle<\/h2>\n<p>The electronic configuration of the metal ion determines how electrons occupy the split d-orbitals, directly impacting CFSE. For instance:<\/p>\n<ul>\n<li><strong>High-spin complexes:<\/strong> Occur when the pairing energy is higher than the crystal field splitting energy (\u0394). These complexes have lower CFSE because electrons occupy higher-energy orbitals before pairing.<\/li>\n<li><strong>Low-spin complexes:<\/strong> Occur when \u0394 is larger than the pairing energy. These complexes exhibit higher CFSE due to maximum occupancy of the lower-energy <code>t_{2g}<\/code> orbitals.<\/li>\n<\/ul>\n<p>For example:<\/p>\n<p>Factors affecting Crystal Field Stabilization Energy CFSE connects to several other topics in the syllabus, making it worth mastering early.<\/p>\n<ul>\n<li><code>[FeF_6]^{3-}<\/code> is a high-spin complex with a lower CFSE due to weak-field <code>F^-<\/code> ligands.<\/li>\n<li><code>[Fe(CN)_6]^{4-}<\/code> is a low-spin complex with a higher CFSE due to strong-field <code>CN^-<\/code> ligands.<\/li>\n<\/ul>\n<p>Understanding these <strong>critical factors affecting crystal field stabilization energy<\/strong> allows you to predict whether a complex will be high-spin or low-spin and its overall stability.<\/p>\n<h2>Worked Example: Calculating CFSE for <strong>Critical Factors Affecting Crystal Field Stabilization Energy<\/strong><\/h2>\n<p>Let\u2019s apply the <strong>critical factors affecting crystal field stabilization energy<\/strong> to calculate CFSE for the complex <code>[Co(NH_3)_6]^{3+}<\/code>.<\/p>\n<p>Clarity on Factors affecting Crystal Field Stabilization Energy CFSE also reduces careless mistakes in numerical and conceptual questions alike.<\/p>\n<p><strong>Step 1: Determine the electronic configuration of Co<sup>3+<\/sup><\/strong><\/p>\n<p>Cobalt (Co) has an atomic number of 27. The electronic configuration of Co<sup>3+<\/sup> is <code>[Ar] 3d^6<\/code>.<\/p>\n<p>Keeping a short, well-organized summary of Factors affecting Crystal Field Stabilization Energy CFSE handy can speed up last-minute revision.<\/p>\n<p><strong>Step 2: Identify the geometry and \u0394<\/strong><\/p>\n<p>The complex <code>[Co(NH_3)_6]^{3+}<\/code> is octahedral with a strong-field ligand (<code>NH_3<\/code>). The crystal field splitting energy (\u0394_o) for this complex is approximately <code>21,000 cm^{-1}<\/code>.<\/p>\n<p>Understanding Factors affecting Crystal Field Stabilization Energy CFSE thoroughly is essential for tackling related exam questions with confidence.<\/p>\n<p><strong>Step 3: Apply the CFSE formula<\/strong><\/p>\n<p>For an octahedral <code>d^6<\/code> low-spin complex, the CFSE is calculated as:<\/p>\n<p>Many aspirants underestimate how often Factors affecting Crystal Field Stabilization Energy CFSE appears across different question formats in these exams.<\/p>\n<p><code>CFSE = 0.4 * \u0394_o + 1.6 * \u0394_o = 2.0 * \u0394_o<\/code><\/p>\n<p>Substituting the value of \u0394_o:<\/p>\n<p>A solid grasp of Factors affecting Crystal Field Stabilization Energy CFSE also helps when questions combine multiple topics in a single problem.<\/p>\n<p><code>CFSE = 2.0 * 21,000 cm^{-1} = 42,000 cm^{-1}<\/code><\/p>\n<p>This high CFSE value explains why <code>[Co(NH_3)_6]^{3+}<\/code> is a stable, low-spin complex.<\/p>\n<p>Revisiting Factors affecting Crystal Field Stabilization Energy CFSE periodically, rather than cramming once, tends to improve long-term retention.<\/p>\n<h2>Common Misconceptions About <strong>Critical Factors Affecting Crystal Field Stabilization Energy<\/strong><\/h2>\n<p>Many students struggle with the <strong>critical factors affecting crystal field stabilization energy<\/strong> due to common misconceptions. Here are a few to avoid:<\/p>\n<ul>\n<li><strong>Misconception:<\/strong> CFSE only depends on the metal ion. <strong>Reality:<\/strong> The <strong>critical factors affecting crystal field stabilization energy<\/strong> include ligands, geometry, and oxidation state.<\/li>\n<li><strong>Misconception:<\/strong> Strong-field ligands always result in low-spin complexes. <strong>Reality:<\/strong> The pairing energy must also be considered. If \u0394 is smaller than the pairing energy, the complex may still be high-spin.<\/li>\n<li><strong>Misconception:<\/strong> CFSE is the same for all octahedral complexes. <strong>Reality:<\/strong> The <strong>critical factors affecting crystal field stabilization energy<\/strong> vary based on ligands, metal ion, and geometry.<\/li>\n<\/ul>\n<p>Clarifying these misconceptions ensures a deeper understanding of the <strong>critical factors affecting crystal field stabilization energy<\/strong>.<\/p>\n<p>Exam setters frequently rephrase questions on Factors affecting Crystal Field Stabilization Energy CFSE, so understanding the underlying logic matters more than memorizing.<\/p>\n<h2>Real-World Applications of <strong>Critical Factors Affecting Crystal Field Stabilization Energy<\/strong><\/h2>\n<p>The <strong>critical factors affecting crystal field stabilization energy<\/strong> are not just theoretical\u2014they have practical applications in various fields:<\/p>\n<ul>\n<li><strong>Catalysis:<\/strong> Understanding CFSE helps in designing catalysts for industrial reactions, such as hydrogenation and polymerization.<\/li>\n<li><strong>Material Science:<\/strong> CFSE influences the properties of metal nanoparticles used in electronics, sensors, and drug delivery systems.<\/li>\n<li><strong>Medicine:<\/strong> Metal complexes with tailored CFSE are used in MRI contrast agents and anticancer drugs.<\/li>\n<\/ul>\n<p>For UPPSC Assistant Professor aspirants, grasping these applications can provide a competitive edge in both theoretical and applied questions.<\/p>\n<p>Building a strong foundation in Factors affecting Crystal Field Stabilization Energy CFSE pays off across several related exam sections.<\/p>\n<h2>Exam Strategy for Mastering <strong>Critical Factors Affecting Crystal Field Stabilization Energy<\/strong><\/h2>\n<p>To excel in questions related to <strong>critical factors affecting crystal field stabilization energy<\/strong>, follow this exam strategy:<\/p>\n<ol>\n<li><strong>Memorize the spectrochemical series:<\/strong> Know the order of ligand field strengths to quickly determine CFSE trends.<\/li>\n<li><strong>Practice CFSE calculations:<\/strong> Work through examples like <code>[Fe(CN)_6]^{4-}<\/code> and <code>[Co(NH_3)_6]^{3+}<\/code> to build confidence.<\/li>\n<li><strong>Understand high-spin vs. low-spin complexes:<\/strong> Learn how \u0394 and pairing energy influence electron configuration.<\/li>\n<li><strong>Relate CFSE to real-world applications:<\/strong> Connect theoretical concepts to catalysis, materials science, and medicine.<\/li>\n<\/ul>\n<p>For additional guidance, explore <a href=\"https:\/\/www.vedprep.com\/\">VedPrep<\/a>\u2019s resources, including video lectures and practice problems tailored to UPPSC Assistant Professor exams. Watch this <a href=\"https:\/\/www.youtube.com\/watch?v=oalXkWZtlQ8\" target=\"_blank\" rel=\"noopener nofollow\">free VedPrep lecture<\/a> on CFSE for a deeper dive into the topic.<\/p>\n<p>Practicing varied problems on Factors affecting Crystal Field Stabilization Energy CFSE is one of the most efficient ways to prepare.<\/p>\n<h2>Frequently Asked Questions About <strong>Critical Factors Affecting Crystal Field Stabilization Energy<\/strong><\/h2>\n<section class=\"vedprep-faq\">\n<h3>Core Understanding<\/h3>\n<div class=\"faq-item\">\n<h4>What is Crystal Field Stabilization Energy (CFSE)?<\/h4>\n<p>CFSE is the energy difference between the d-orbitals of a metal ion in a complex and those in a spherical field. It quantifies the stabilization energy gained due to the interaction between the metal ion and ligands, and it is influenced by the <strong>critical factors affecting crystal field stabilization energy<\/strong>.<\/p>\n<\/div>\n<div class=\"faq-item\">\n<h4>Why are the <strong>critical factors affecting crystal field stabilization energy<\/strong> important?<\/h4>\n<p>The <strong>critical factors affecting crystal field stabilization energy<\/strong> determine the stability, color, and magnetic properties of metal complexes. Understanding these factors is essential for predicting complex behavior in both theoretical and applied chemistry.<\/p>\n<\/div>\n<div class=\"faq-item\">\n<h4>How does ligand field strength influence CFSE?<\/h4>\n<p>Ligand field strength directly affects CFSE by determining the magnitude of \u0394. Strong-field ligands increase \u0394, leading to higher CFSE, while weak-field ligands decrease \u0394, resulting in lower CFSE.<\/p>\n<\/div>\n<div class=\"faq-item\">\n<h4>What role does the coordination number play in CFSE?<\/h4>\n<p>The coordination number influences the geometry of the complex, which in turn affects the splitting of d-orbitals. For example, octahedral complexes (CN = 6) exhibit higher CFSE compared to tetrahedral complexes (CN = 4).<\/p>\n<\/div>\n<div class=\"faq-item\">\n<h4>How does the oxidation state of the metal ion affect CFSE?<\/h4>\n<p>A higher oxidation state increases the charge on the metal ion, strengthening its interaction with ligands and thus increasing \u0394 and CFSE.<\/p>\n<\/div>\n<h3>Exam Application<\/h3>\n<div class=\"faq-item\">\n<h4>How can I apply CFSE to solve problems in UPPSC Assistant Professor exams?<\/h4>\n<p>Focus on understanding the <strong>critical factors affecting crystal field stabilization energy<\/strong>, such as ligand field strength, coordination number, and \u0394. Practice calculating CFSE for different complexes and relate these concepts to real-world applications.<\/p>\n<\/div>\n<div class=\"faq-item\">\n<h4>What are common questions related to CFSE in UPPSC exams?<\/h4>\n<p>Common questions include calculating CFSE for given complexes, explaining the factors affecting CFSE, and predicting the stability and magnetic properties of complexes based on their CFSE values.<\/p>\n<\/div>\n<div class=\"faq-item\">\n<h4>Can you explain how to calculate CFSE for a given complex?<\/h4>\n<p>To calculate CFSE, determine the electronic configuration of the metal ion, identify the geometry and \u0394, and apply the appropriate formula based on whether the complex is high-spin or low-spin.<\/p>\n<\/div>\n<h3>Common Mistakes<\/h3>\n<div class=\"faq-item\">\n<h4>What are common mistakes students make when calculating CFSE?<\/h4>\n<p>Common mistakes include misidentifying the geometry of the complex, incorrectly assigning electron configurations, and overlooking the influence of ligand field strength on \u0394.<\/p>\n<\/div>\n<div class=\"faq-item\">\n<h4>How can I avoid mistakes when applying CFSE to transition elements?<\/h4>\n<p>Ensure you thoroughly understand the <strong>critical factors affecting crystal field stabilization energy<\/strong>, such as the spectrochemical series and the relationship between \u0394 and CFSE. Practice with a variety of examples to build confidence.<\/p>\n<\/div>\n<\/section>\n<\/article>\n","protected":false},"excerpt":{"rendered":"<p>Understanding Factors affecting Crystal Field Stabilization Energy (CFSE) For UPPSC Assistant Professor exams is crucial for improving your CSIR NET\/IIT JAM\/GATE score with VedPrep. The topic falls under Chapter 1 of Inorganic Chemistry in the official CSIR NET and NTA syllabus, titled &#8216;Coordination Compounds&#8217;.<\/p>\n","protected":false},"author":12,"featured_media":21580,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"footnotes":"","_debug_hook_fired":"2026-07-30 01:33:57","rank_math_seo_score":0},"categories":[352],"tags":[2923,17919,17920,17921,17922,2922],"class_list":["post-21581","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-uppsc","tag-competitive-exams","tag-factors-affecting-crystal-field-stabilization-energy-cfse-for-uppsc-assistant-professor","tag-factors-affecting-crystal-field-stabilization-energy-cfse-for-uppsc-assistant-professor-notes","tag-factors-affecting-crystal-field-stabilization-energy-cfse-for-uppsc-assistant-professor-questions","tag-upsc-assistant-professor-exam-preparation","tag-vedprep","entry","has-media"],"acf":[],"rank_math_title":"Factors Affecting Crystal Field Stabilization Energy Cfse","rank_math_description":"Factors affecting Crystal Field Stabilization Energy CFSE. Discover the top 5 critical factors affecting crystal field stabilization energy (CFSE) for UPPSC.","rank_math_focus_keyword":"Factors affecting Crystal Field Stabilization Energy CFSE","_links":{"self":[{"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/posts\/21581","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/users\/12"}],"replies":[{"embeddable":true,"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/comments?post=21581"}],"version-history":[{"count":1,"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/posts\/21581\/revisions"}],"predecessor-version":[{"id":32705,"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/posts\/21581\/revisions\/32705"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/media\/21580"}],"wp:attachment":[{"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/media?parent=21581"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/categories?post=21581"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.vedprep.com\/exams\/wp-json\/wp\/v2\/tags?post=21581"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}